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A-Team

5 bytes added, 1 April
Initial implementation
float sum = 0.0f;
for (int k = 0; k < nk; k++)
sum += d_a[i * nk + k] * d_b[k * nj + j]; d_p[i * nj + j] = sum;
}
}
=== Assignment 3 ===
113
edits

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