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→xor_me
At first it seems impossible to do because of the data dependencies: hash, r[1], t[1], and o. But after doing some research, I have learned that the XOR operation is communicative and associative, meaning that we can simply calculate all of the dependencies in parallel first, then combine the results to achieve the same data.
Here is a non-formal proof to help make my point clear. The ability to achieve the same result vertically and horizontally will be the key to solving this task.
<pre>
Step 1:
101 ^ 001 ^ 111 = 001
111 ^ 100 ^ 001 = 010
100 ^ 010 ^ 001 = 111
|| || ||
110 111 111
Step 2: Operate with vertical and horizontal
001 ^ 010 ^ 111 = 110
110 ^ 111 ^ 111 = 110
</pre>
=== Assignment 3 ===
