Difference between revisions of "K2"

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(Assignment2)
(Assignment2)
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Third box is stage 2 and it has 2 rounds. In first round, there are 2 orange and green boxes that contains 4 elements. in this case, index 0 and 2 and 1 and 3 will be compared and sorted in ascending if orange box and in descending if green box. then in round 2, index 0 and 1 , 2 and 3 ... will be compared and sorted. Third box and Fourth box are same.
 
Third box is stage 2 and it has 2 rounds. In first round, there are 2 orange and green boxes that contains 4 elements. in this case, index 0 and 2 and 1 and 3 will be compared and sorted in ascending if orange box and in descending if green box. then in round 2, index 0 and 1 , 2 and 3 ... will be compared and sorted. Third box and Fourth box are same.
  
[[File:source.jpg]]
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[[File:bitonicLaunch.jpg]]

Revision as of 18:14, 15 April 2018

Team members


Assignment1

What is Bitonic sorting algorithm?

Bitonic mergesort is a parallel algorithm for sorting. It is also used as a construction method for building a sorting network. The algorithm was devised by Ken Batcher. The resulting sorting networks consist of O( n log^2( n )) comparators and have a delay of O( log^2( n )) , where n is the number of items to be sorted.(https://en.wikipedia.org/wiki/Bitonic_sorter)

The process of bitonic algorithm












(https://www.geeksforgeeks.org/bitonic-sort/)


Analysis and Profiling

The bitonic sorting algorithm is devised for the input length n being a power of 2. To check the noticeable time gap, we put 2^15, 2^20, 2^25.

void bitonicSort(int* array, int N){
int i,j,k;
    for (k=2;k<=N;k=2*k) {
      for (j=k>>1;j>0;j=j>>1) {
        for (i=0;i<N;i++) {
          int ixj=i^j;
          if ((ixj)>i) {
            if ((i&k)==0 && array[i]>array[ixj]){
              int temp=array[i];
              array[i]=array[ixj];
              array[ixj]=temp;
            } 
            if ((i&k)!=0 && array[i]<array[ixj]){
              int temp=array[i];
              array[i]=array[ixj];
              array[ixj]=temp;
            } 
          }
        }
      }
    }
}

Flat profile


The size of array:2^16(65536)

Each sample counts as 0.01 seconds.
  %   cumulative   self              self     total           
 time   seconds   seconds    calls  ms/call  ms/call  name    
100.00      0.07     0.07        1    70.00    70.00  bitonicSort(int*, int)
  0.00      0.07     0.00        1     0.00     0.00  _GLOBAL__sub_I__Z11bitonicSortPii
  0.00      0.07     0.00        1     0.00     0.00  generateRandom(int*, int)
  0.00      0.07     0.00        1     0.00     0.00  __static_initialization_and_destruction_0(int, int)

The size of array:2^20(1048576)

Each sample counts as 0.01 seconds.
  %   cumulative   self              self     total           
 time   seconds   seconds    calls   s/call   s/call  name    
 98.94      1.87     1.87        1     1.87     1.87  bitonicSort(int*, int)
  1.06      1.89     0.02        1     0.02     0.02  generateRandom(int*, int)
  0.00      1.89     0.00        1     0.00     0.00  _GLOBAL__sub_I__Z11bitonicSortPii
  0.00      1.89     0.00        1     0.00     0.00  __static_initialization_and_destruction_0(int, int)

The size of array:2^24(16777216)

Each sample counts as 0.01 seconds.
  %   cumulative   self              self     total           
 time   seconds   seconds    calls   s/call   s/call  name    
 99.53     41.98    41.98        1    41.98    41.98  bitonicSort(int*, int)
  0.47     42.18     0.20        1     0.20     0.20  generateRandom(int*, int)
  0.00     42.18     0.00        1     0.00     0.00  _GLOBAL__sub_I__Z11bitonicSortPii
  0.00     42.18     0.00        1     0.00     0.00  __static_initialization_and_destruction_0(int, int)

Assignment2

BitonicSort1.png

First, array is unsorted array.

second box is stage 1, and orange boxes are sorted in ascending order and green boxes are sorted in descending order. Third box is stage 2 and it has 2 rounds. In first round, there are 2 orange and green boxes that contains 4 elements. in this case, index 0 and 2 and 1 and 3 will be compared and sorted in ascending if orange box and in descending if green box. then in round 2, index 0 and 1 , 2 and 3 ... will be compared and sorted. Third box and Fourth box are same.

BitonicLaunch.jpg