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C/C++ FAQ

21 bytes added, 17:30, 1 October 2012
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In the case of overloaded functions the only thing they have in common is the name. Signatures are different, hence the same pointer to function can't be used for both of them.<br>
Back to your question. Call to Function Pointer will call an overloaded function with the same signature as the Function Pointer. (<br><b>Answer is Submitted by :</b> Team42)
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